12 条题解

  • 2
    @ 2025-12-3 18:43:11
    #include <iostream>
    using namespace std;
    int main(){
        int a=0,n;
        cin>>n;
        for(int i=1;i<=n;i++){
        	a=a+i;
    	}
    	cout<<a;
        return 0;
    }
    • 1
      @ 2025-9-7 20:10:02

      一次过

      #include <algorithm>
      #include <bitset>
      #include <cctype>
      #include <cerrno>
      #include <clocale>
      #include <cmath>
      #include <complex>
      #include <cstdio>
      #include <cstdlib>
      #include <cstring>
      #include <ctime>
      #include <cwchar>
      #include <cwctype>
      #include <complex.h>
      #include <deque>
      #include <exception>
      #include <fstream>
      #include <functional>
      #include <fenv.h>
      #include <iomanip>
      #include <ios>
      #include <iosfwd>
      #include <iostream>
      #include <istream>
      #include <inttypes.h>
      #include <limits>
      #include <list>
      #include <map>
      #include <ostream>
      #include <queue>
      #include <set>
      #include <sstream>
      #include <stack>
      #include <stdexcept>
      #include <streambuf>
      #include <string>
      #include <stdbool.h>
      #include <stdint.h>
      #include <tgmath.h>
      #include <utility>
      #include <vector>
      using namespace std;
      #define LL long long
      const int N = 1e5 + 10;
      const int INF = 0x3f3f3f3f;
      
      int main() {
      	int n , ans = 0;
      	cin >> n;
      	for(int i = 1 ; i <= n ; i++){
      		ans += i;
      	}
      	cout << ans;
          return 0;
      }
      
      • 0
        @ 2025-12-21 23:15:25

        好简单,只需要记 高斯求和公式(等差数列)

        a1+a2++an=(a1+an)n÷2a1+a2+…+an=(a1+an)n÷2

        就🆗了

        • 0
          @ 2025-11-29 13:12:43

          #include<bits/stdc++.h> using namespace std; int main() {
          int n; cin>>n; cout<<(1+n)*n/2; return 0; }

          • -1
            @ 2025-7-10 17:18:20

            #include #include #include using namespace std; int n , sum; int main() {

            cin>>n;
            for(int i = 1 ; i <= n; i++)
            {
              sum += i;	
            }	
            cout << sum;
            return 0;
            

            }

            • -1
              @ 2024-12-18 21:11:22
              #include <bits/stdc++.h>
               using namespace std; 
              int n;
              int main()
              {
              cin>>n;
              cout<<(1+n)*n/2;
              }
              
              • -1
                @ 2023-11-24 18:48:51

                还行

                • -1
                  @ 2023-4-26 18:37:22

                  #include using namespace std; int n,ans; int main() { cin>>n; for(int i=1;i<=n;i++) { ans += i; } cout <<ans; return 0; }

                  • -1
                    @ 2022-12-15 20:07:04
                    #include<iostream>
                    using namespace std;
                    int main(){
                    	long long n;
                    	cin>>n;
                    	cout<<(1+n)*n/2;
                    }
                    

                    一个字符都不想多打了

                    • -2
                      @ 2024-6-21 19:36:19

                      #include <bits/stdc++.h> using namespace std; int main(){ int n,num=0; cin>>n; for(int i=1;i<=n;i++){ num+=i; } cout<<num; return 0; }

                      | col1


                      | col2 | col3 | | --- | --- | --- | | | | | | | | |

                      • -2
                        @ 2023-4-2 20:30:30
                        #include<iostream>
                        using namespace std;
                        int main(){
                        	long long n;
                        	cin>>n;
                        	cout<<(1+n)*n/2;
                        }
                        
                        • -2
                          @ 2022-4-25 21:58:56

                          #include

                          using namespace std;

                          int main(){

                          int a;
                          
                          cin >> a;
                          
                          a = (1 + a) * a / 2;
                          
                          cout << a << endl;
                          

                          }

                          • 1

                          信息

                          ID
                          906
                          时间
                          1000ms
                          内存
                          128MiB
                          难度
                          5
                          标签
                          递交数
                          946
                          已通过
                          389
                          上传者