• a = int(input())
• if a % 3 == 0 and a % 5 != 0 and a % 7 != 0:
• print("3")
• if a % 5 == 0 and a % 3 !=0 and a % 7 != 0:
• print("5")
• if a % 7 == 0 and a % 3 !=0 and a % 5 != 0:
• print("7")
• if a % 3 == 0 and a % 5 == 0 and a % 7 != 0:
• print("3 5")
• if a % 3 == 0 and a % 7 == 0 and a % 5 != 0:
• print("3 7")
• if a % 5 == 0 and a % 7 == 0 and a % 3 !=0:
• print("5 7")
• if a % 3 == 0 and a % 5 == 0 and a % 7 == 0:
• print("3 5 7")
• if a % 3 != 0 and a % 5 != 0 and a % 7 != 0:
• print("n")

各位的题解都这么复杂？ 最简题解（目前）：

#include <stdio.h>
int main() {
    int n;
    scanf("%d", &n);
    bool a = false;

    if (n % 3 == 0) {
        printf("%d ", 3);
        a = true;
    }

    if (n % 5 == 0) {
        printf("%d ", 5);
        a = true;
    }

    if (n % 7 == 0) {
        printf("%d ", 7);
        a = true;
    }

    if (!a)
        printf("n");

}

其中的a用于判断是否无法被任何数输出。

hhh a = int(input()) if a % 3 == 0 and a % 5 != 0 and a % 7 != 0: print("3") if a % 5 == 0 and a % 3 !=0 and a % 7 != 0: print("5") if a % 7 == 0 and a % 3 !=0 and a % 5 != 0: print("7") if a % 3 == 0 and a % 5 == 0 and a % 7 != 0: print("3 5") if a % 3 == 0 and a % 7 == 0 and a % 5 != 0: print("3 7") if a % 5 == 0 and a % 7 == 0 and a % 3 !=0: print("5 7") if a % 3 == 0 and a % 5 == 0 and a % 7 == 0: print("3 5 7") if a % 3 != 0 and a % 5 != 0 and a % 7 != 0: print("n")

a = int(input()) if a % 3 == 0 and a % 5 != 0 and a % 7 != 0: print("3") if a % 5 == 0 and a % 3 !=0 and a % 7 != 0: print("5") if a % 7 == 0 and a % 3 !=0 and a % 5 != 0: print("7") if a % 3 == 0 and a % 5 == 0 and a % 7 != 0: print("3 5") if a % 3 == 0 and a % 7 == 0 and a % 5 != 0: print("3 7") if a % 5 == 0 and a % 7 == 0 and a % 3 !=0: print("5 7") if a % 3 == 0 and a % 5 == 0 and a % 7 == 0: print("3 5 7") if a % 3 != 0 and a % 5 != 0 and a % 7 != 0: print("n")