#include<iostream>
#include<math.h>
#include<stdio.h>
using namespace std;
int n;
double a[301],sum;
int main(){
	cin>>n;
	double maxx=pow(10,-9),minn=pow(10,9);
	for(int i=1;i<=n;i++){
		cin>>a[i];
		maxx=max(a[i],maxx);
		minn=min(a[i],minn);
	}
	for(int i=1;i<=n;i++){
		if(a[i]!=maxx&&a[i]!=minn)sum+=a[i];//判断有效样本
	}
	double jz=sum/(n-2),num=pow(10,-9);//均值与最大误差
	for(int i=1;i<=n;i++){
		if(a[i]!=maxx&&a[i]!=minn)num=max(num,fabs(a[i]-jz));
	}
	printf("%.2lf %.2lf",jz,num);
	return 0;
}